Answer:
The value of the test statistic is [tex]t = 2.1[/tex]
Step-by-step explanation:
Our test statistic is:
[tex]t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the expected value, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
The level of ozone normally found is 7.5 parts/million (ppm).
This means that [tex]\mu = 7.5[/tex]
The mean of 24 samples is 7.8 ppm with a standard deviation of 0.7.
This means that [tex]X = 7.8, \sigma = 0.7, n = 24[/tex]
Test Statistic:
[tex]t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]t = \frac{7.8 - 7.5}{\frac{0.7}{\sqrt{24}}}[/tex]
[tex]t = 2.1[/tex]
The value of the test statistic is [tex]t = 2.1[/tex]
