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D and E are any two points on the sides AB and AC respectively of the triangle ABC. DG drawn parallel to BE meets AC in G and EF drawn parallel to CD meets AB in F. Prove that FG is parallel to BC.

Respuesta :

Step-by-step explanation:

FG//BC

FG=g - f

but f = a + b ÷ 2

and g = a + c ÷ 2

g - f

a + c / 2 - a + b /2

c - b /2 =BC

hence FG // BC

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