Answer:
139 mL
Explanation:
Given data:
Volume of solution required = ?
Molarity of solution = 0.222 M
Mass of salt = 9.57 g
Solution:
Number of moles of manganese iodide:
Number of moles = mass/molar mass
Number of moles = 9.57 g/ 308.75 g/mol
Number of moles = 0.031 mol
Volume required:
Molarity = number of moles of solute / volume in L
0.222 M = 0.031 mol / V
V = 0.031 mol / 0.222 mol/L
V = 0.139 L
Volume in mL:
0.139 L ×1000 mL / 1 L
139 mL
