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A space shuttle burns fuel at the rate of 13,000kg in each second. Find the force exerted by the fuel on the shuttle if in 2s the shuttle experiences a change in momentum of 325,000kgm/s.

Respuesta :

Answer:

162,500

Explanation:

P=F(t)

32500=F(2)

162,500

The force exerted by the fuel on the shutter will be "162500 N". To understand the calculation, check below.

Force and Momentum

According to the question,

Change in momentum, ΔP = 325,000 kg.m/s

Time, Δt = 2 sec

Mass = 13,000 kg

We know the relation,

Force, F = [tex]\frac{dP}{dt}[/tex] or,

                 = [tex]\frac{\Delta P}{\Delta t}[/tex]

                 = [tex]\frac{Change \ in \ momentum}{Time}[/tex]

By substituting the values,

                 = [tex]\frac{325000}{2}[/tex]

                 = 162500 N

Thus the above answer is correct.

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