Answer:
Question 5
We get n=42.15 and o=71.5
Question 6
We get e=15.32 and t=17.88
Step-by-step explanation:
Question 5
The triangles are similar.
So, the ratio of corresponding sides will be similar.
[tex]\frac{53}{n}=\frac{88}{70}=\frac{90}{o}[/tex]
First we will solve [tex]\frac{53}{n}=\frac{88}{70}[/tex] to find value of n.
Cross multiply
[tex]53*70=88*n\\n=\frac{3710}{88}\\n=42.15\\[/tex]
Now, we will solve [tex]\frac{88}{70}=\frac{90}{o}[/tex] to find value of o
[tex]88*o = 90*70\\o=\frac{6300}{88}\\o=71.5\\[/tex]
So, We get n=42.15 and o=71.5
Question 6
The triangles are similar.
So, the ratio of corresponding sides will be similar.
[tex]\frac{9.6}{e}=\frac{5.7}{9.1}=\frac{11.2}{t}[/tex]
First we will solve [tex]\frac{9.6}{e}=\frac{5.7}{9.1}[/tex] to find value of n.
Cross multiply
[tex]9.1*9.6=e*5.7\\e=\frac{87.36}{5.7}\\e=15.32\\[/tex]
Now, we will solve [tex]\frac{5.7}{9.1}=\frac{11.2}{t}[/tex] to find value of o
[tex]5.7*t = 11.2*9.1\\t=\frac{101.92}{5.7}\\t=17.88\\[/tex]
So, We get e=15.32 and t=17.88
