Answer:
[tex]y=3(x-2)^2[/tex]
Step-by-step explanation:
The vertex form of the quadratic function has the following equation:
[tex]y=a(x-h)^2+k[/tex]
Where (h, k) is the vertex of the parabola, and a is a coefficient different from zero.
We are given the vertex located at (2,0). The equation is now:
[tex]y=a(x-2)^2+0[/tex]
[tex]y=a(x-2)^2[/tex]
Since we know the point (1,3) is on the parabola:
[tex]3=a(1-2)^2[/tex]
3=a(1)
a = 3
Finally, the quadratic equation is:
[tex]\mathbf{y=3(x-2)^2}[/tex]
