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1. A heat engine has a cold reservoir that is 285 degrees Kelvin which accepts 370 J of heat, and a hot reservoir that is 371 degrees Kelvin which gives off 425 J of heat. Calculate the maximum and actual efficiencies of this engine.


2. A system that has a total change in entropy of 675 J/K and has received 243 J of heat energy will be at what temperature?


3. Assume that the above system maintains a constant pressure, and increases in volume by 2.5 m 3 while doing this work. What is the pressure of the system?

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emmaandears

I can't help with this one.

onyebuchinnaji

The maximum efficiency of the heat engine is 23%.

The actual efficiency of the heat engine is 13%.

The temperature of the system is 273.36 ⁰C.

The pressure of the system is 607.5 Pa.

The given parameters:

  • Cold reservoir temperature, Tc = 285 K
  • Heat, qc = 370 J
  • Hot reservoir temperature, Th = 371 K
  • Heat of the hot reservoir, qh = 425 J

The maximum efficiency of the heat engine is calculated as follows;

[tex]\eta = 1- \frac{T_c}{T_h} \\\\ \eta = 1 - \frac{285}{371} \\\\ \eta = 0.23\\\\ \eta = 23 \ \%[/tex]

The actual efficiency of the heat engine is calculated as follows;

[tex]\eta = 1 - \frac{q_c}{q_h} \\\\ \eta = 1 - \frac{370}{425} \\\\ \eta = 0.13\\\\ \eta = 13\ \%[/tex]

The temperature of the system is calculated as follows;

[tex]\Delta S = \frac{\Delta H}{T} \\\\ T = \frac{\Delta H}{\Delta S}\\\\ T = \frac{243}{675} \\\\ T = 0.36 \ K\\\\ T = 273.36 \ ^0C[/tex]

The pressure of the system is calculated as follows;

[tex]W = P \Delta V\\\\ P = \frac{W}{\Delta V} \\\\ P = \frac{243}{2.5} \\\\ P = 607.5 \ Pa[/tex]

Learn more about efficiency of heat engine here: https://brainly.com/question/10955336

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