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1. How many moles of iron is needed to react with sulfur in order to produce 8.6 moles
of iron (III) sulfide according to the following equation?2Fe + 3S --> Fe253

Respuesta :

jufsanabriasa

Answer:

17.2 moles of Iron are required

Explanation:

Based on the chemical reaction:

2Fe + 3S → Fe₂S₃

2 moles of Fe react with 3 moles of S to produce 1 mole of Iron (III) sulfide

Assuming and excess of sulfur, if we want to obtain 8.6 moles of Fe₂S₃ are required:

8.6 moles Fe₂S₃ * (2 moles Fe / 1mol Fe₂S₃) =

17.2 moles of Iron are required

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