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A 52.6 kg car is driving at a constant velocity of 20 m/s over 2 seconds. What is its acceleration?

Respuesta :

Answer:

Centripetal acceleration is related to tangential velocity through ac = v ^ 2 / R

The angular velocity is related to the tangential velocity through ω = v / R

a) ac = (20 m / s) ^ 2/20 m = 20 m / s ^ 2

b) ω = 20 m / s / 20m = 1 rad / s

c) The swept angle is Ф = ω.t = 1 rad / s. 3600 s = 3600 rad

Expressed in turns it is Ф = 3600 rad. 1 turn / (2.π rad) = 573 turn

Explanation: