edgarlola2
contestada

Drag each equation to the correct location on the table.
Match the inequalities with the value of a for which they hold true.
2a + 3 < 9 - 3a
14 + 5a < 12a + 1
2a + 3 > 10 - 3a
4 + 3a +8 < 16
3a - 2a +1>2
5a - 4a + 6 < 8

Drag each equation to the correct location on the table Match the inequalities with the value of a for which they hold true 2a 3 lt 9 3a 14 5a lt 12a 1 2a 3 gt class=

Respuesta :

Answer:

Hi! I hope this is correct please inform me if this is incorrect :)

a = 1 will have.

2a + 3 < 9 - 3a.  

2a + 3 > 10 -3a.  

3a - 2a + 1>2.

a = 2 will have

ANY others I did not include in a = 1 :)

Please once again tell me if this is incorrect.

Step-by-step explanation:

Inequality (1), (4) and (7) are true for a=1 and inequality (2), (3) and (5) are true for a=2.

We need to determine which inequalities are true for a=1 and a=2.

What are inequalities?

In mathematics, an inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

Now, put a=1 inequalities and check.

1) 2(1) + 3 < 9 - 3(1)⇒5<6

2) 14 + 5(1) < 12(1) + 1⇒19>13

3) 2(1) + 3 > 10 - 3(1)⇒5<7

4)  4 + 3(1) +8 < 16⇒15<16

5) 3(1)- 2(1)+1>2⇒2=2

6) 5(1)- 4(1)+ 6 < 8⇒7<8

So, inequality (1), (4) and (7) are true for a=1.

1) 2(2) + 3 < 9 - 3(2)⇒7>6

2) 14 + 5(2) < 12(2) + 1⇒24<25

3) 2(2) + 3 > 10 - 3(2)⇒7>4

4)  4 + 3(2) +8 < 16⇒18>16

5) 3(2)- 2(2)+1>2⇒3>2

6) 5(2)- 4(2)+ 6 < 8⇒8=8

So, inequality (2), (3) and (5) are true for a=2.

Therefore, inequality (1), (4) and (7) are true for a=1 and inequality (2), (3) and (5) are true for a=2.

To learn more about inequality visit:

https://brainly.com/question/20383699.

#SPJ2

Otras preguntas