Find the area of the regular polygon?

Answer:
20.76
Step-by-step explanation:
Find the area of one triangle and multiply it by 6:
Let H be the midpoint of AB,[tex]\triangle GAB\\|AB| = 2\sqrt{2}\\H = (-2, 3) => |GH| = \sqrt{(-2-(-3.73))^{2} + (3 - 4.73)^{2}} = \sqrt{1.73^{2}+1.73^{2}}=1.73\sqrt{2}\\A = 6 * \frac{|AB||GH|}{2} = 3 * 2\sqrt{2}*1.73\sqrt{2} = 20.76[/tex]