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Answer:

John will be 16 years old when he is twice as old as his brother, which will then be 8.

Step-by-step explanation:

Currently John is 12, and is three times as old as his brother thus, his brother is 12 divided by 3, which is 4 years old.

Thus when John is 12, his brother is 4. There is thus a 8 year difference between the two brothers.

So we can write a small equation to solve John’s age when he will be twice as old.

John’s age = X

John’s Brothers age = X - 8

Thus : X - 8 = X/2, John’s age minus the difference of 8 years must equal John’s age divided by 2, to make John twice as old as his brother.

X - 8 = x/2

X = X/2 + 8

(2*X)/2 = (X/2) + (16/2) - Place all numbers as fractions of 2 by multiplying x 2

2*X = X + 16

2*X -X = 16

X+X -X = 16

X = 16

John’s age will be 16 when he is twice as old as his brother which will be 8.

John : 16 - 12 = 4 : Subtract current Age

His Brother: 8 - 4 = 4 : Subtract current Age

In 4 years time John will be twice as old as his brother

16 = 8 * 2

The age of Bob and John is 6 and 18 respectively.

According to the question;

  • Bob is 12 years younger than john.
  • In essence, x = y - 12........eqn(1)

and

  • John is 3 times as old as Bob
  • y = 3x...........eqn(2)

where; x = Bob's age and y = John's age.

By substituting 3x for y in equation (1). We have;

  • x = 3x -12
  • x -3x = -12
  • -2x = -12
  • x = 6.

Therefore, since, x = 6;

  • y = 3 × 6 = 18.

Ultimately, The age of Bob and John is 6 and 18 respectively.

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