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A coconut falls out of a tree 12.0 m above the ground and hits a bystander 3.00 m tall on the top of the head. It bounces back up 1.50 m before falling to the ground. If the mass of the coconut is
2.00 kg, calculate the potential energy of the coconut relative to the ground at each of the following sites:
(a) while it is still in the tree,
(b) when it hits the bystander on the head,
(c) when it bounces up to its maximum height,
(d) when it lands on the ground,
(e) when it rolls into a groundhog hole, and falls 2.50 m to the bottom of the hole.

Respuesta :

Eduard22sly

Answer:

A. 240 J

B. 60 J

C. 90 J

D. 0 J

E. 50 J

Explanation:

A. Determination of the potential energy of the coconut while it is still in the tree

Mass (m) = 2 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 12 m

Potential energy (PE) =.?

PE = mgh

PE = 2 × 10 × 12

PE = 240 J

B. Determination of the potential energy of the coconut when it hits the bystander on the head,

Mass (m) = 2 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 3 m

Potential energy (PE) =.?

PE = mgh

PE = 2 × 10 × 3

PE = 60 J

C. Determination of the potential energy of the coconut when it bounces up to its maximum height,

Mass (m) = 2 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 3 + 1.5 = 4.5 m

Potential energy (PE) =.?

PE = mgh

PE = 2 × 10 × 4.5

PE = 90 J

D. Determination of the potential energy of the coconut when it lands on the ground,

Mass (m) = 2 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 0 m

Potential energy (PE) =.?

PE = mgh

PE = 2 × 10 × 0

PE = 0 J

E. Determination of the potential energy of the coconut when it rolls into a ground hole, and falls 2.50 m to the bottom of the hole.

Mass (m) = 2 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 2.50 m

Potential energy (PE) =.?

PE = mgh

PE = 2 × 10 × 2.50

PE = 50 J

onyebuchinnaji

(a) The potential energy of the coconut relative to the ground while it is still in the tree is 235.2 J.

(b) The potential energy of the coconut relative to the ground when it hits the bystander on the head is 58.8 J.

(c) The potential energy of the coconut relative to the ground when it bounces up to its maximum height is 88.2 J.

(d) The potential energy of the coconut relative to the ground when it lands on the ground is 0 J.

(e) The potential energy of the coconut when it rolls into a groundhog hole, and falls 2.50 m to the bottom of the hole is 49 J.

The given parameters;

  • height of the tree, h = 12 m
  • height of the bystander, h' = 3 m
  • height it bounced back = 1.5 m
  • mass of the coconut, m = 2.0 kg

The potential energy of the coconut relative to the ground while it is still in the tree;

[tex]P.E = mgh\\\\P.E = 2 \times 9.8 \times 12\\\\P.E = 235.2 \ J[/tex]

The potential energy of the coconut relative to the ground when it hits the bystander on the head;

[tex]P.E = 2 \times 9.8 \times 3 \\\\P.E = 58.8 \ J[/tex]

The potential energy of the coconut relative to the ground when it bounces up to its maximum height;

[tex]P.E = 2 \times 9.8 (1.5 + 3)\\\\P.E = 88.2 \ J[/tex]

The potential energy of the coconut relative to the ground when it lands on the ground;

[tex]P.E = 2 \times 9.8 \times 0\\\\P.E = 0 \ J[/tex]

The potential energy of the coconut relative to the ground when it rolls into a groundhog hole, and falls 2.50 m to the bottom of the hole;

[tex]P.E = 2\times 9.8 \times 2.5 \\\\P.E = 49 \ J[/tex]

Learn more about potential energy here: https://brainly.com/question/18160141

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