Answer:
3.26×10⁵ L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 3.5×10⁵ L
Initial temperature (T₁) = 27 °C
Initial pressure (P₁) = 101 KPa
Final temperature (T₂) = –10 °C
Final pressure (P₂) = 95 KPa
Final volume (V₂) =?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(ºC) + 273
Initial temperature (T₁) = 27 °C
Initial temperature (T₁) = 27 °C + 273
Initial temperature (T₁) = 300 K
Final temperature (T₂) = –10 °C
Final temperature (T₂) = –10 °C + 273
Final temperature (T₂) = 263 K
Finally, we shall determine the new volume of the tank. This can be obtained as follow:
Initial volume (V₁) = 3.5×10⁵ L
Initial temperature (T₁) = 300 K
Initial pressure (P₁) = 101 KPa
Final temperature (T₂) = 263 K
Final pressure (P₂) = 95 KPa
Final volume (V₂) =?
P₁V₁ / T₁ = P₂V₂ / T₂
101 × 3.5×10⁵ / 300 = 95 × V₂ / 263
117833.333 = 95 × V₂ / 263
Cross multiply
95 × V₂ = 117833.333 × 263
95 × V₂ = 30990166.6
Divide both side by 95
V₂ = 30990166.6 / 95
V₂ = 3.26×10⁵ L
Thus, the new volume of the tank is 3.26×10⁵ L
