Step-by-step explanation:
Let x be the number.
We have 17x - x² > 60.
=> x² - 17x + 60 < 0
=> (x - 5)(x - 12) < 0
=> 5 < x < 12
Hence the number is between 5 and 12, both non-inclusive.
The number must be between [tex]5[/tex] and [tex]12[/tex].
A square number is the result when a number has been multiplied by itself.
Let the number be [tex]x[/tex].
As [tex]17[/tex] times a number is decreased by the square of the same number, the result is greater than [tex]60[/tex],
[tex]17x-x^{2}>60[/tex]
[tex]x^{2} -17x+60<0[/tex]
[tex]x^{2}-12x-5x+60<0[/tex]
[tex]x(x-12)-5(x-12)<0[/tex]
[tex](x-5)(x-12)<0[/tex]
[tex]5<x<12[/tex]
So, the number must be between [tex]5[/tex] and [tex]12[/tex]
For more information:
https://brainly.com/question/17379629?referrer=searchResults
