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2. A pharmaceutical chemist runs a chromatography test on a substance
and identifies two of its components by comparing their Ry values
against certain standards. If the two components have Rf values of 1.0
and 0.41, and the solvent front has travelled 12.0 cm from the sample's
origin, what is the separation distance on the chromatogram?

Respuesta :

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Answer:

7.08 cm

Explanation:

For number 1;

Rf = d1/d2

d1/12 cm

Rf = 1.0

d1 = 12 * 1

d1 = 12.0 cm

For number 2

Rf = d1/d2

Rf = 0.41

0.41= d1/12

d1 = 0.41 * 12

d1 = 4.92 cm

Separation distance= 12.0 - 4.92 = 7.08 cm

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