Answer:
Total distance covered = 436 yards
Step-by-step explanation:
Walking path BE joins the midpoints B and E of the sides AC and AD.
By midsegment theorem,
"Line joining midpoints of two sides of a triangle is parallel and measure half of the third side"
m(BE) = [tex]\frac{1}{2}[m(CD)][/tex]
CD = 2(BE)
CD = 2(74) = 128 yd
From starting point D,
DE = 107 yd
EB = 74 yd
BC = [tex]\frac{254}{2}[/tex]
= 127 yd
CD = 128 yd
Total walking distance = DE + EB + BC + CD
= 107 + 74 + 127 + 128
= 436 yd
Total distance covered = 436 yards
