The solution to the system of equation is (7, 2)
Using the simultaneous equation:
5x + 3y = 41
2x + 3y = 20
using elimination method
Subtract equation 1 from 2 to have:
5x - 2x = 41 - 20
3x = 21
x = 21/3
x = 7
Substitute x = 7 into equation 1 to get y
5x + 3y = 41
5(7) + 3y = 41
35 + 3y = 41
5y = 41 - 35
3y = 6
y = 6/3
y = 2
Hence the solution to the system of equation is (7, 2)
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