Respuesta :
Given :
A compound has a molar mass of 129 g/mol .
Empirical formula of compound is C₂H₅N .
To Find :
The molecular formula of the compound.
Solution :
Empirical mass of compound :
[tex]M_e = ( 2 \times 12 ) + ( 5 \times 1 ) + ( 1 \times 14 )\\\\M_e = 43\ gram/mol[/tex]
Now, n-factor is :
[tex]n = \dfrac{M}{M_e}\\\\n = \dfrac{129}{43}\\\\n = 3[/tex]
Multiplying each atom in the formula by 3 , we get :
Molecular Formula, C₆H₁₅N₃
The molecular formula of the compound is C₆H₁₅N₃.
Calculation:
The Empirical mass of the compound is
[tex]= (2\times 12) + (5\times 1) + (1\times 14)\\\\[/tex]
= 43 gram/mol
Now n-factor should be
[tex]= 129 \div 43[/tex]
= 3
Now here we multiply every atom in the formula by 3 so it should be C₆H₁₅N₃
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