Answer:
sin5A+sin3A=cos2A-cos6A
2SIN((5A+3A)/2)COS ((5A-3A)/2)=2SIN((2A+6A)/2)SIN((2A-6A)/2)
[tex] \frac{2 \sin(4a )cosa}{ - 2 \sin(4a) \sin(2a) } = 1[/tex]
[tex] - \frac{ \cos(a) }{2 \sin(a) \cos(a ) } = 1[/tex]
-1/2sinA=1
-1/2=sinA
sinA=sin(180+30),sin(330)
:.A=210,330
