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Answer:

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Step-by-step explanation:

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The required polynomial in standard form with zeros –4, 0, 1, and 4 is x⁴- x³ - 16x²+16x

Polynomial functions are functions that have a leading variable of 3 and above.

Given the zeros of a polynomial as -4, 0, 1, and 4, their corresponding factors will be:

(x+4)), x-0, x-1 and x - 4

To get the polynomial function required, we will take the product of the factors as shown:

= x(x-1)(x+4)(x-4)

= (x²-x)(x²-4²) (Note that (x+4)(x-4) is from different of two square)

f(x)= x⁴-16x²-x³+16x

Rearranging

f(x) = x⁴- x³ - 16x²+16x

Hence the function x⁴- x³ - 16x²+16x gives the required polynomial in standard form.

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