This question is incomplete, the complete complete question is;
Coulomb's law for the energy of interaction between two charged ions;
E = Ke × q1q2/r
Coulomb's constant Ke = 2.31 × 10⁻²⁸ J.m.
Calculate the bond energy in the ionic compound NaCl if the bond length is 2.36 × 10⁻¹⁰m
Answer:
the bond energy is -9.788 × 10⁻¹⁹ J
Explanation:
Given the data in the question;
Ke = 2.31 × 10⁻²⁸ J.m which is the same as; Ke = 2.31 × 10⁻²⁸ Nm L/c²
ionic compound NaCl;
q1 = charge on Na in NaCl = Na⁺ = + 1C
q2 = charge on Cl in NaCl = Cl⁻ = - 1C
given that bond length r is 2.36 × 10⁻¹⁰m
E = Ke × q1q2/r
we substitute
E = 2.31 × 10⁻²⁸ × (+1 × -1) / 2.36 × 10⁻¹⁰
E = -2.31 × 10⁻²⁸ / 2.36 × 10⁻¹⁰
E = -9.788 × 10⁻¹⁹ J { The negative sign means Attraction in ions }
Therefore, the bond energy is -9.788 × 10⁻¹⁹ J
