HELPPPP: From the top of a light house 50 meters high, the angle of depression of a boat out at sea has a measure of 15°. Find to the nearest meter the distance from the boat to the foot of the light house, which is at sea level.

Answer:
13m
Step-by-step explanation:
[tex]d=50tan(15)=13m[/tex]
The required distance from the boat to the foot of the light house, which is at sea level is 13meter
Given that,
The top of a light house 50 meters high,
The angle of depression of a boat out at sea has a measure of 15°.
We have to determine,
To the nearest meter the distance from the boat to the foot of the light house, which is at sea level.
According to the question,
The angle of depression may be found by using this formula = opposite/adjacent.
The opposite side in this case is usually the height of the observer or height in terms of location.
Therefore, angle of depression = 15degree
Height of the light house = 50m
The distance from the boat of the light house is denoted by d.
Then the distance from the boat of the light house is given as.
[tex]tan15 = \frac{d}{50} \\\\d = 50 \times tan15\\\\d = 50\times0.26\\\\d = 13[/tex]
Hence, The required distance from the boat to the foot of the light house, which is at sea level is 13meter
For more information about Trigonometry click the link given below.
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