Answer:
-86.02 kJ/ mole
Explanation:
The moles of the acid used = Molarity × Volume (L) =
= 0.50 (0.0372 L)
= 0.0186 moles
The heat released = -1.6 kJ
∴ 0.0186 moles neutralization of HA heat is: -1.6 kJ
The molar heat of neutralization due to one mole of the unknown acid = -1.6/0.0186
= -86.02 kJ/ mole
The molar heat of neutralization for the unknown acid is -86.02 kJ/ mole.
The moles of the acid used = Molarity × Volume (L) =
= 0.50 (0.0372 L)
= 0.0186 moles
Thus, the moles of the acid used is 0.0186.
The heat released = -1.6 kJ
Thus, 0.0186 moles neutralization of HA heat is: -1.6 kJ
Molar heat of Neutralization: It is the amount of heat each mole of base added to the acid (or vice versa) causes the reaction to give off.
The molar heat of neutralization due to one mole of the unknown acid = [tex]\frac{-1.6}{0.0186}=-86.02kJ/mole[/tex]
So, the molar heat of neutralization is -86.02kJ/mole.
Find more information about Moles here:
brainly.com/question/13314627
