Answer: y=0
Step-by-step explanation:
Mid point of line segment joining (a,b) and (p,q) = [tex](\dfrac{a+p}{2},\dfrac{b+q}{2})[/tex]
Mid point of line segment joining the points (-1,3) and (5,-3) = [tex](\dfrac{-1+5}{2},\dfrac{3-3}{2})[/tex]
[tex]=(\dfrac42,\dfrac02)\\= (2,0)[/tex]
Equation of line passing through (a,b) and (c,d) is given by :-
[tex](y-b)=\dfrac{d-b}{c-a}(x-a)[/tex]
Equation of line passing through (2,0) and (0,0) will be:
[tex](y-0)=\dfrac{0-0}{2-0}(x-0)\\\\\\ y=0[/tex]
