The net horizontal force on a box F as a function of the
horizontal position x is shown below.
Force (N)
40
20+
Position (m)
4
4
6
oc
10
12
14
-20+
-40
What is the work done on the box from x = 0m to
16 m?
Round answer to two significant digits.
J

The Workdone is the product of force and distance, Hence, the Workdone on the box from distance x = 0 meters and x = 16 meters is 0 Joules.

Using the graph given :

The work done from x = 0 to x = 16 metres ;

The distance can be split evenly into :

(x = 0 to x = 8) and (x = 8 to x = 16)

Workdone = Force × distance

Workdone from ; x = 0 to x = 8 ;

Force at a distance of 8 meters = - 40N

Workdone = - 40N × 8 m = -320 Nm

Workdone from ; x = 8 to x = 16 ;

Force at a distance of 16 meters = 40 N

Workdone = 40 N × 8 m = 320 Nm

The total workdone :

(-320 + 320) Nm = 0 J

.

Therefore, the Workdone ls 0 Joules.

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The net horizontal force on a box F as a function of the horizontal position x is shown below. Force (N) 40 20+ Position (m) 4 4 6 oc 10 12 14 -20+ -40 What is the work done on the box from x = 0m to 16 m? Round answer to two significant digits. J

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The net horizontal force on a box F as a function of the
horizontal position x is shown below.
Force (N)
40
20+
Position (m)
4
4
6
oc
10
12
14
-20+
-40
What is the work done on the box from x = 0m to
16 m?
Round answer to two significant digits.
J