Answer:
See explanation
Explanation:
We know that
%ic of the interatomic bond = [1 - e^-(XA - XB)^2/4] * 100%
Now;
XA = electronegativity of Ti = 1.61
XB = electronegativity of Al = 1.54
Substituting values;
%ic of the interatomic bond = [1 - e^-(1.61 - 1.54)^2/4] * 100%
%ic of the interatomic bond = 0.12%
Given the low %ic of the interatomic bond, the bond is metallic.
The percent ionic character is 0% and the type of interatomic bonding would be metallic.
The percent ionic character can be determined by using the formula,
[tex]1-exp{-0.25(Xa-Xb)^{2} ][/tex]
• In the given equation, Xa and Xb refers to the electronegativities of the elements.
• The intermetallic compound given is TiAl₃.
• Based on the electronegativity table, the electronegativity of Al or Xa is 1.5 and the electronegativity of Ti or Xb is 1.5.
Now putting the values in the above formula we get the % ionic character,
[tex]= 1-exp [-0.25 (Xa -Xb)^{2}]*100%\\\\\\=1-exp [-0.25 (1.5 -1.5)^{2}]*100%\\[/tex]
[tex]= 0 percent[/tex]
Thus, the ionic bond character is 0% and the compound TiAl₃ comprises two metals, it exhibits metallic bonding.
To know more about:
https://brainly.com/question/10889818
