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Logan measured a line to be 7.4 inches long. If the actual length of the line is 7.7 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

Respuesta :

adedamolaogunlela

Step-by-step explanation:

Error = 7.7-7.4=0.3

% error= 0.3/7.7×100 % error= 3.89%

= 3.9% to the nearest tenth

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