Respuesta :
Answer:
1) The frequency of each photon is 3.0 × 10⁹ Hz
2) The energy of each photon is 1.98786 × 10⁻²⁴ J
Explanation:
The energy, 'E', in a photon of light is given by Planck's equation as follows;
E = h·f = h·c/λ
Where;
E = The energy of a photon
h = Planck constant = 6.6262 × 10⁻³⁴ J·s
f = The frequency of the photon/radiation
c = The speed of light = 3.0 × 10⁸ m/s
λ = The wavelength of the photon/radiation
The given parameters of the microwave are;
The wavelength, λ = 10 cm = 0.1 m
The type of wave = Microwave
1) From E = h·f = h·c/λ, we find that the frequency, 'f' equals c/λ
∴ f = 3.0 × 10⁸ m/s/(0.1 m) = 3.0 × 10⁹ 1/s = 3.0 × 10⁹ Hz
The frequency of each photon, f = 3.0 × 10⁹ Hz
2) From E = h·f = h·c/λ, the energy, 'E', of each photon is given as follows;
E = h·c/λ = 6.6262 × 10⁻³⁴ J·s × 3.0 × 10⁸ m/s/(0.1 m) = 1.98786 × 10⁻²⁴ J
The energy of each photon, E = 1.98786 × 10⁻²⁴ J
