Answer:
The depth of the object below the surface of the liquid is 0.510 meters.
Explanation:
The hydrostatic pressure ([tex]P[/tex]), measured in pascals, experimented by the object is directly proportional to density of the fluid ([tex]\rho[/tex]), measured in kilograms per cubic meter, gravitational acceleration ([tex]g[/tex]), measured in meters per square second, and depth of the object ([tex]h[/tex]), measured in meters. That is:
[tex]P = \rho\cdot g \cdot h[/tex] (1)
If we know that [tex]P = 4500\,Pa[/tex], [tex]\rho = 900\,\frac{kg}{m^{3}}[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then the depth of the object is:
[tex]h = \frac{P}{\rho\cdot g}[/tex]
[tex]h = \frac{4500\,Pa}{\left(900\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}[/tex]
[tex]h = 0.510\,m[/tex]
The depth of the object below the surface of the liquid is 0.510 meters.
