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In a reaction that produces carbon dioxide, the theoretical yield is 59 grams. During the experiment, the reaction actually produced 52.9 grams of carbon dioxide. Determine the percent yield.

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Answer:

mole ratio, which is equivalent to a 1;1 mole ratio, to a gram ratio. This means that when the reaction consumes 84.03 g of carbon monoxide, it should theoretically produce 132.03 g of carbon dioxide. Use this gram ratio to calculate the theoretical yield for your reaction.

Explanation:

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