Answer: 682 grams
Explanation:
The balanced chemical reaction is:
[tex]4Fe+3O_2\rightarrow 2Fe_2O_3[/tex]
[tex]O_2[/tex] is the limiting reagent as it limits the formation of product and [tex]Fe[/tex] is the excess reagent.
According to stoichiometry :
3 moles of [tex]O_2[/tex] produce = 2 moles of [tex]Fe_2O_3[/tex]
Thus 6.40 moles of [tex]O_2[/tex] will produce=[tex]\frac{2}{3}\times 6.40=4.27moles[/tex] of [tex]Fe_2O_3[/tex]
Mass of [tex]Fe_2O_3=moles\times {\text {Molar mass}}=4.27moles\times 159.69g/mol=682g[/tex]
Thus 682 g of [tex]Fe_2O_3[/tex] will be produced from 6.40 moles of oxygen
