Respuesta :
Answer: Its x-intercepts are at (0,0) and (11,0) and The x-coordinate of its vertex is 5.5
Step-by-step explanation: In the equation you see the negative 11 which would mean it is actually a postive 11 when shown on a graph. Then the x would be considered as (0,0) and notice its the things in the parentheses. The vertex is what we is the center or the lowest or highest point in a quadrilateral line. Its the number between the two coordinates [(0,0) and (11,0)] and that would be 5.5. Referring to the x-coordinates

x-intercepts of the parabola are (0, 0) and (11, 0)
x-coordinate of the vertex is x = 5.5
Properties of a quadratic equation:
- x-intercepts of a quadratic equation are the points where y = 0.
- y-intercepts of a quadratic equation are the points where x = 0.
- If the equation of a quadratic equation is in the vertex form,
y = a(x - h)² + k
Vertex of the parabola will be (h, k)
Given in the question,
- Equation of the parabola → y = 2x(x - 11)
Convert the equation in the vertex form,
y = 2x² - 22x
y = 2(x² - 11x)
y = 2[x² - 2(5.5x) + (5.5)² - (5.5)²]
y = 2[(x - 5.5)² - 30.25]
y = 2(x - 5.5)² - 60.5
Vertex of the parabola will be (5.5, -60.5).
For x-intercepts,
Substitute y = 0,
0 = 2x(x - 11)
⇒ x = 0, 11
Therefore, x-intercepts of the parabola will be (0, 0) and (11, 0).
Hence, x-intercepts of the parabola are (0, 0) and (11, 0)
x-coordinate of the vertex is x = 5.5
Learn more about the quadratic equations here,
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