Select all true statements about the graph that represents y = 2x (x - 11) Its x-intercepts are at (-2.0) and (11,0) a Its x-intercepts are at (0,0) and (11,0) Its x-intercepts are at (2.0) and (-11,0) It has only one x-intercept The x-coordinate of its vertex is -4.5 The x-coordinate of its vertex is 11 The x-coordinate of its vertex is 4.5 The x-coordinate of its vertex is 5.5​

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Answer: Its x-intercepts are at (0,0) and (11,0) and The x-coordinate of its vertex is 5.5

Step-by-step explanation: In the equation you see the negative 11 which would mean it is actually a postive 11 when shown on a graph. Then the x would be considered as (0,0) and notice its the things in the parentheses. The vertex is what we is the center or the lowest or highest point in a quadrilateral line. Its the number between the two coordinates [(0,0) and (11,0)] and that would be 5.5. Referring to the x-coordinates

Ver imagen williyah06

x-intercepts of the parabola are (0, 0) and (11, 0)

x-coordinate of the vertex is x = 5.5

Properties of a quadratic equation:

  •  x-intercepts of a quadratic equation are the points where y = 0.
  •  y-intercepts of a quadratic equation are the points where x = 0.
  •  If the equation of a quadratic equation is in the vertex form,

          y = a(x - h)² + k

          Vertex of the parabola will be (h, k)

Given in the question,

  •  Equation of the parabola → y = 2x(x - 11)

Convert the equation in the vertex form,

y = 2x² - 22x

y = 2(x² - 11x)

y = 2[x² - 2(5.5x) + (5.5)² - (5.5)²]

y = 2[(x - 5.5)² - 30.25]

y = 2(x - 5.5)² - 60.5

    Vertex of the parabola will be (5.5, -60.5).

For x-intercepts,

Substitute y = 0,

0 = 2x(x - 11)

⇒ x = 0, 11

    Therefore, x-intercepts of the parabola will be (0, 0) and (11, 0).

Hence, x-intercepts of the parabola are (0, 0) and (11, 0)

            x-coordinate of the vertex is x = 5.5

Learn more about the quadratic equations here,

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