find the value of x to the nearest tenth

Answer:
Look below.
Step-by-step explanation:
Good ol' Pythagorean Theorem.
To find the short side of the larger triangle, we'll use this equation:
[tex]a^{2} +b^{2} =c^{2} \\\\9^2+b^2=10^2\\81+b^2=100\\[/tex]
You can solve the rest on your own.
Use the same type of equation for the smaller triangle, except your b would be the hypotenuse, so that equation would look something like this:
[tex]3^2+x^{2} = b^2[/tex]
Hope it helped! Also, there seems to be a help video, if you didn't understand this explanation, why don't you go ahead and watch it?
Answer:
x ≈ 3.2
Step-by-step explanation:
Using Pythagoras' identity in the right triangle on the left
let third side be h , then
h² + 9² = 10²
h² + 81 = 100 ( subtract 81 from both sides )
h² = 19
Using Pythagoras' identity in the right triangle on the right
x² + 3² = h²
x² + 9 = 19 ( subtract 9 from both sides )
x² = 10 ( take the square root of both sides )
x = [tex]\sqrt{10}[/tex] ≈ 3.2 ( to the nearest tenth )