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How many gallons of a 30% alcohol solution must be mixed with 60 gallons of a 14% solution to obtain a solution that is 20% alcohol?

Respuesta :

jramosm243

Answer:  A=3.6

Step-by-step explanation: let A= # of gallons of 30% solution of alcohol

.3A+60(.14)=.2(60+A)

.3A+8.4=12+.2A----->subtract .2A and 8.4 from each side highlight%28A=36%29 gallons of 30% solution of alcohol