Answer:
[tex]y=\frac{2}{3} x-1[/tex]
Step-by-step explanation:
Linear equations are typically organized in slope-intercept form:
[tex]y=mx+b[/tex] where [tex]m[/tex] is the slope and [tex]b[/tex] is the y-intercept (the value of y when the line intercepts the y-axis)
1) Find the slope of the line (m)
The equation for slope: [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] when the given points are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Plug in the given points (3,1) and (6,3)
[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]=\frac{3-1}{6-3}\\=\frac{2}{3}[/tex]
Now, plugging this back into [tex]y=mx+b[/tex], our equation looks like this:
[tex]y=\frac{2}{3} x+b[/tex]
2) Find the y-intercept of the line
To find the y-intercept, we take the equation that we have so far and plug in any given point to solve for b. For example, we can use the point (3,1):
[tex]1=\frac{2}{3}*3+b\\1=2+b[/tex]
Subtract both sides by 2 to isolate b
[tex]1-2=2+b-2\\-1=b[/tex]
3) Plug m and b into y=mx+b
[tex]y=\frac{2}{3} x-1[/tex]
I hope this helps!
