The gradient of the straight-line that passes through the points, (-2, 3) and (1,9) is: 2.
Recall:
- Gradient of a line = slope (m) = change in y/change in x
- Gradient (m) = [tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex]
Given two points on a straight line as: (-2, 3) and (1,9)
(-2, 3) = [tex](x_1, y_1)[/tex]
(1, 9) = [tex](x_2, y_2)[/tex]
Plug in the values into the slope/gradient formula
[tex]Gradient = \frac{9 - 3}{1 - (-2)} \\\\Gradient = \frac{6}{3}\\\\\mathbf{Gradient = 2}[/tex]
Therefore, the gradient of the straight-line that passes through the points, (-2, 3) and (1,9) is: 2.
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