Answer:
4.86moles of barium sulfide are produced
Explanation:
To solve this question we need to convert the mass of barium sulfide (BaS) to moles using the molar mass of BaS:
Molar mass BaS:
1 Ba atom = 137.3g/mol
1 S atom = 32.1g/mol
Molar mass BaS = 137.3 + 32.1 = 169.4g/mol
Moles in 823g of BaS:
823g * (1mol / 169.4g) =