Answer:
Options (B) and (E)
Step-by-step explanation:
Area of ΔABC = [tex]\frac{1}{2}(\text{Base})(\text{Height})[/tex]
= [tex]\frac{1}{2}(14)(6)[/tex]
= 42 in²
Area of trapezoid ADEC = [tex]\frac{1}{2}(b_1+b_2)h[/tex]
[Here, [tex]b_1[/tex] and [tex]b_2[/tex] are the parallel sides and 'h' is the height of the isosceles trapezoid given]
= [tex]\frac{1}{2}(10+14)(8)[/tex]
= 96 in²
Area of the pentagon = Area of triangle ABC + Area of trapezoid ADEC
= 42 + 96
= 138 in²
Therefore, Options (B) and (E) are the correct options.
