The Ferrari with less momentum will stop first.
The given parameters:
- Mass of the freight, m1 = 5000 ton = 4535924 kg
- Speed of the freight, v1 = 10 mph = 4.47 m/s
- Mass of the Ferrari, m2 = 3250 lb = 1474.175 kg
- Speed of the Ferrari, v2 = 250 mph = 111.76 m/s
The momentum of each vehicle is calculated as follows;
P1 = m1v1 = 4535924 x 4.47 = 20,275,580.28 kgm/s
P2 = m2v2 = 1474.175 x 111.76 = 164,753.8 kgm/s
[tex]Ft = mv\\\\t = \frac{mv}{F}[/tex]
When the same force is applied, the object will less momentum will stop first.
Since the vehicle less momentum will stop first, thus we can conclude that the Ferrari with less momentum will stop first.
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