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A 2.00L mixture of helium, nitrogen, and neon has a total pressure of 815 mmHg at a
temperature of 255K. If the partial pressure of helium is 201 mmHg and the partial
pressure of nitrogen is 351 mmHg, what is the partial pressure of neon in the mixture?
O 709 mmHg
O 512 mmHg
O 667 mmHg
O 263 mmHg

Respuesta :

Answer: The partial pressure of neon in the mixture is 263 mm Hg

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

[tex]p_{total}=p_{He}+p_{N_2}+p_{Ne}[/tex]

Given : [tex]p_{total}[/tex] =total pressure of gases = 815 mm Hg

[tex]p_{He}[/tex] = partial pressure of helium = 201 mm Hg

[tex]p_{N_2}[/tex] = partial pressure of nitrogen = 351 mm Hg

[tex]p_{Ne}[/tex] = partial pressure of Neon = ?

putting in the values we get:

[tex]815mm Hg=201 mm Hg+351 mm Hg+p_{Ne}[/tex]  

[tex]p_{Ne}=263mmHg[/tex]

The partial pressure of neon in the mixture is 263 mm Hg

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