You open a savings account and deposit $1,000. After 1 year of earning continuously compounded interest.
your balance is $1.018.16. After 2 years, the balance is $1.036.66. Assuming you make no deposits or
withdrawals, find the equation for the best-fitting exponential function to represent the balance of the account
after x years. How much money will be in the account after 10 years?

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Answer:

Step-by-step explanation:

[tex]1036.66=1000e^{2r}\\ \\ r=(ln(1.03666))/2\\ \\ r=0.018\\ \\ b(x)=1000e^{(0.018x)}\\ \\ b(10)=1000e^{0.18}=\$ 1197.22[/tex]

The equation for the best-fitting exponential function is A = 1000 (1.01816)ˣ. And the amount of money in the account after 10 years will be $ 1197.18.

What is compound interest?

Compound interest is the interest on a loan or deposit calculated based on the initial principal and the accumulated interest from the previous period.

You open a savings account and deposit $1,000.

After 1 year of earning continuously compounded interest.

Your balance is $1.018.16. After 2 years, the balance is $1.036.66.

Assuming you make no deposits or withdrawals.

Then the equation for the best-fitting exponential function represents the balance of the account after x years will be

A = 1000(1 + r/100)ˣ

After one year, the amount will be 1018.16 dollars. Then the value of r will be

 1018.16 = 1000 (1 + r/100)¹

1 + r/100 = 1.01816

    r/100 = 0.01816

           r = 1.816%

Then the equation will be

A = 1000 (1.01816)ˣ

Then the amount of money in the account after 10 years will be

A = 1000 (1.01816)¹⁰

A = 1000 x 1.19718

A = $ 1197.18

More about the compound interest link is given below.

https://brainly.com/question/25857212

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