Given:
A 6 sided die is rolled.
To find:
The probability of getting not 5, i.e., P( not 5).
Solution:
If a 6 sided die is rolled, then the possible outcomes are 1, 2, 3, 4, 5, 6.
Total outcomes = 6
Favorable outcomes = Possible numbers other than 5 = 5
Now,
[tex]P(\text{ not 5})=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]
[tex]P(\text{ not 5})=\dfrac{5}{6}[/tex]
[tex]P(\text{ not 5})=0.8333...[/tex]
[tex]P(\text{ not 5})\approx 0.83[/tex]
Therefore, the probability of getting not 5, i.e., P( not 5) is 0.83.
