Answer and Step-by-step explanation:
So, we are given that the slope of side AB is -3.
Let's draw out a right triangle. C
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A B
So, we see side AB, and side BC.
(Don't look at AB as a straight line like this, imagine it slanted if you want to)
If the slope is -3, and the intersection of AB and BC make a perpendicular, then a slope of [tex]\frac{1}{3}[/tex] would cause the right angle to form.
So, [tex]\frac{1}{3}[/tex] is the slope of BC.
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