Respuesta :

mhanifa

Answer:

  • 1. ∠C = 90°
  • 2. ∠B = 90°
  • 3. ∠BAD = 90°
  • 4. ∠ADC = 90°
  • 5. ∠EDC = 90° - 53° = 37°
  • 6. ∠EDF = ∠DEC = 53°
  • 7. ∠FED = 90° - 53° = 37°
  • 8. ∠FEA = 90° - ∠FED = 90° - 37° = 53°
  • 9. ∠EFA = 90°
  • 10. ∠FAE = 90° - ∠FEA = 90° - 53° = 37°
  • 11. ∠EAB = 90° - ∠FAE = 90° - 37° = 53°
  • 12. ∠AEB = 90° - ∠EAB = 90° - 53 = 37°

Answer:

Answer:

90°

90°

90°

90°

edc=180-90-53=37by sum of angle of triangle

edf=90-37=53

fed=cde=53alternate angle

fea=180-fae-efa=180-37-90=53

efa=180-90=90linear pair

fae=180-<e-edf=180-90-53=37

eab=90-fae=90-37=53

aeb=180-b-bae=180-90-53=37