Answer:
[tex]\boxed {\boxed {\sf 447,560 \ Joules}}[/tex]
Explanation:
We are asked to find the energy required to melt 1340 grams of ice. We are given this formula:
[tex]Q=mL[/tex]
In this formula, Q is the heat, m is the mass, and L is the latent heat.
For this problem, the mass is 1340 grams of ice. Since we want to melt the ice, we need the latent heat of fusion (melting) which is 334 Joules per gram.
[tex]m= 1340 \ g \\L= 334 \ J/g[/tex]
Substitute the values into the formula.
[tex]Q= (1340 \ g )( 334 \ J/g)[/tex]
Multiply. The grams will cancel each other out.
[tex]Q=1340 *334 \ J \\Q=447560 \ J[/tex]
447,560 Joules of energy are needed to melt 1340 grams of ice.
