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Write a rational function for the given scenario. There may be more than one correct answer.

Question 1. X-intercept: none
Vertical Asymptote: X = -3
Horizontal Asymptote: y = 0

Question 2. X-intercept: none
Vertical Asymptote X=2 & x= -2
Horizontal Asymptote: y = 0

Question 3 x-intercept: (3,0) & (-3,0) Vertical Asymptote: X=-1 & x= -4
Horizontal Asymptote: y = 1

Question 4. X-intercept: (-2, 0)
Vertical Asymptote: X = 4 & x=-5 Horizontal Asymptote: y=0

Need to make a rational function for each question.

Respuesta :

Ln26931

Answer:

Q1:     [tex]\frac{1}{x+3}[/tex]

Q2:     [tex]\frac{1}{(x-2)(x+2)}[/tex]

Q3:     [tex]\frac{(x-3)(x+3)}{(x+1)(x+4)}[/tex]

Q4:     [tex]\frac{x(x+2)}{(x-4)^{2}(x+5) }[/tex]

Step-by-step explanation:

If there is a vertical asymptote at x=k, then the denominator must contain a term (x-k) or (x-k) raised to a positive integer power.

If there is an x intercept at k, then the numerator must contain a term (x-k) or (x-k) raised to a positive integer power.

If there is a horizontal asymptote of 0, then the highest power of x in the denominator must exceed the highest power of x in the numerator.

If thee is a horizontal asymptote of k, then the highest power of x in the numerator and denominator must be the same and the ratio of their coefficients (numerator to denominator) must be k.