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The specific heat of liquid H2O is 4.184 J/g°C. If 32.7 grams of water are heated from
12 °C to 77 °C, how much energy is required?

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ASAP please will mark as brainlist don’t got much time

The specific heat of liquid H2O is 4184 JgC If 327 grams of water are heated from 12 C to 77 C how much energy is required Look at picture ASAP please will mark class=

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arkog476

Answer:

8893.092J

Explanation:

energy= mass × specific heat capacity of water × change in temperature

=32.7×4.184×(77-12)

=8893.092J

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