○=> Solution (6) :
Ratio of two numbers = 2:3
The larger number = 6
Let the smaller number be x.
Which means :
[tex] =\tt 2 : 3 \: = \: x : 6[/tex]
[tex] = \tt \frac{2}{3} = \frac{x}{6} [/tex]
[tex] =\tt 2 \times 6 = 3 \times x[/tex]
[tex] =\tt 12 = 3x[/tex]
[tex] =\tt x = \frac{12}{3} [/tex]
[tex]\hookrightarrow\color{plum}\tt \: x = 4[/tex]
▪︎Therefore, the smaller number = 4
○=> Solution (7) :
36 compared to 6 = [tex] \tt \frac{36}{6} [/tex]
Let the number be x.
Which means :
[tex] = \tt \frac{36}{6} = \frac{x}{3} [/tex]
[tex] =\tt \frac{36 \div 2}{6 \div 2} = \frac{x}{3} [/tex]
[tex] =\tt \frac{36}{6} = \frac{18}{3} [/tex]
▪︎Therefore, the fractional number [tex] \tt \frac{18}{3} [/tex] is equal to [tex] \tt \frac{36}{6} [/tex].
○=> Solution (8) :
Number of Rose's for 24 red Rose's = 6
This can be written in a ratio as 24:6
Number of roses = 8
Let the number of red roses for these roses be x.
Which means :
[tex] =\tt \frac{24}{6} = \frac{x}{8} [/tex]
[tex] =\tt 24 \times 8 = 6 \times x[/tex]
[tex] =\tt 192 = 6x[/tex]
[tex] =\tt x = \frac{192}{6} [/tex]
[tex]\hookrightarrow \color{plum}\tt x = 32[/tex]
▪︎Therefore, 32 red roses are there if there are 8 roses.
○=> Solution (9) :
Number of children for 2 adults = 7
This can be written in a ratio as 7:2
Number of children in the plaza = 21
Let the number of adults be x.
Which means :
[tex] = \tt \frac{7}{2} = \frac{21}{x} [/tex]
[tex] =\tt7 \times x = 2 \times 21 [/tex]
[tex] =\tt 7x = 42[/tex]
[tex] =\tt x = \frac{42}{7} [/tex]
[tex] \hookrightarrow \color{plum}\tt \: x = 6[/tex]
▪︎Therefore, 6 adults were there in the plaza.
○=> Solution (10) :
Cost of 12 pencils = P60
Cost of 1 pencil :
[tex] = \tt \frac{60}{12} [/tex]
[tex] =\tt P5[/tex]
Thus, the cost of one pencil = P5
Cost of 25 pencils :
= Cost of one pencil × 25
[tex] =\tt 5 \times 25[/tex]
[tex] \color{plum}=\tt \: P \: 125[/tex]
▪︎Therefore, the cost of 25 pencils = P125
