Answer: 0.91 g of methane is required.
Explanation:
The balanced chemical equation will be:
[tex]CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)[/tex]
The mole ratio of [tex]CH_4[/tex] : [tex]H_2O[/tex] = 1: 2
Molar masses of [tex]CH_4[/tex] : [tex]H_2O[/tex] = 16: 18
36 g of water is produced from = 16 g of [tex]CH_4[/tex]
Thus 2.05 g of water is produced from = [tex]\frac{16}{36}\times 2.05=0.91g[/tex] of [tex]CH_4[/tex]
Thus in order to calculate the mass of produce produced when the mass of reactant is given we first need to write the balanced equation. Then the mole ratio is determined and then molar masses and dimensional analysis is used to find the mass of product.
